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## #26 2013-03-11 05:29:26

Al-Allo
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### Re: Algebra -Subject

Okay, Im here. And Bobbym, really haven't you ANY suggestions on how to begin these equations ? I'm feeling that there is no methodology in what Im doing...

## #27 2013-03-11 05:33:36

bobbym

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### Re: Algebra -Subject

It does take experience to do some of these. You gain that experience by doing them. The beginning stuff is right here:

http://www.mathsisfun.com/algebra/equat … lving.html

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #28 2013-03-11 05:43:37

Al-Allo
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### Re: Algebra -Subject

Yes, I guess I'll still keep practicing. thanks

## #29 2013-03-11 05:46:55

bobbym

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### Re: Algebra -Subject

Can you get c as the subject?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Al-Allo
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c=b+2/a

## #31 2013-03-11 05:55:53

bobbym

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### Re: Algebra -Subject

That is correct!

Make b the subject.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #32 2013-03-11 06:01:30

Al-Allo
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### Re: Algebra -Subject

Just a question, If I distribute the b on the right, I must also distribute it for 2 ? (Must I distribute to all the right side of the equation ?

1/a=2b ?

## #33 2013-03-11 06:06:35

bobbym

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### Re: Algebra -Subject

Hi;

I am not following you. What are you trying to do?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #34 2013-03-11 06:14:43

Al-Allo
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### Re: Algebra -Subject

Im trying to isolate b on the right of the equation, but must I also distribute the B to the whole right side of the equation ?

*b 1/a=1/b+2 *b (to the 1/b AND to the 2)

which gives :
b/a=2b

?

Last edited by Al-Allo (2013-03-11 06:15:06)

## #35 2013-03-11 06:19:59

Al-Allo
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### Re: Algebra -Subject

Foget my question, heres my answer b=2a

## #36 2013-03-11 06:22:54

bobbym

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### Re: Algebra -Subject

Hi;

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #37 2013-03-11 06:24:03

Al-Allo
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### Re: Algebra -Subject

*b   1/a= 1b +2 *b

b/a=+2

## #38 2013-03-11 06:25:27

bobbym

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### Re: Algebra -Subject

The left side is correct.

When you multiply the right side by b, that means everything on the right gets multiplied by b. Try it again.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #39 2013-03-11 06:28:19

Al-Allo
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### Re: Algebra -Subject

Sorry Bobbym, Ive got other to finish. Il try it on my own, Im feelng that Im lacking knowledge in algebra, maybe I should do a review ^^

## #40 2013-03-11 06:34:00

bobbym

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### Re: Algebra -Subject

You only need some practice on that type.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.