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You are not logged in. #1 20070923 15:40:13
Mean quiz :PA friend of mine posted this mean quiz on facebook: Code:Quiz() Prgm ClrIO For a, 4, 10, 2 0 > j If a = 10 j+1 > j For b, 1, 4, 1 If a/b=iPart(a/b) Then a/b > c For d, 1, 4, 1 d*c > e If e = 4 or e = 6 or e = 8 or e = 10 Then If e = 10 and a = 10 j+1 > j for f, 5, 9, 2 15f = g If g = 10 and e = 10 and a = 10 j+1 > j a+g > h If h = 7 or h = 9 or h = 9 or h = 13 Then For i, 1, 4, 1 1/3i^32i^2+17/3i > i For k, 1, 4, 1 1/3k^3+2k^22/3k > k i  k > L For m, 2, 5, 1 m+hl > n For p, 1, 4, 1 0 > z If isPrime(a) = true z+1 > z If isPrime(b) = true z+1 > z If isPrime(c) = true z+1 > z If isPrime(d) = true z+1 > z If isPrime(e) = true z+1 > z If isPrime(f) = true z+1 > z If isPrime(g) = true z+1 > z If isPrime(h) = true z+1 > z If isPrime(i) = true z+1 > z If isPrime(j) = true z+1 > z If isPrime(k) = true z+1 > z If isPrime(l) = true z+1 > z If isPrime(m) = true z+1 > z If isPrime(n)= true z+1 > z If isPrime(p) = true z+1 > z If z = a Then 0 > z If 2^x=a and x = iPart(x) z+1 > z If 2^x=b and x = iPart(x) z+1 > z If 2^x=c and x = iPart(x) z+1 > z If 2^x=d and x = iPart(x) z+1 > z If 2^x=e and x = iPart(x) z+1 > z If 2^x=f and x = iPart(x) z+1 > z If 2^x=g and x = iPart(x) z+1 > z If 2^x=h and x = iPart(x) z+1 > z If 2^x=i and x = iPart(x) z+1 > z If 2^x=j and x = iPart(x) z+1 > z If 2^x=k and x = iPart(x) z+1 > z If 2^x=l and x = iPart(x) z+1 > z If 2^x=m and x = iPart(x) z+1 > z If 2^x=n and x = iPart(x) z+1 > z If 2^x=p and x = iPart(x) z+1 > z If z = m Then 0 > z If x*(x+1)/2=a and x=iPart(x) z+1 > z If x*(x+1)/2=b and x=iPart(x) z+1 > z If x*(x+1)/2=c and x=iPart(x) z+1 > z If x*(x+1)/2=d and x=iPart(x) z+1 > z If x*(x+1)/2=e and x=iPart(x) z+1 > z If x*(x+1)/2=f and x=iPart(x) z+1 > z If x*(x+1)/2=g and x=iPart(x) z+1 > z If x*(x+1)/2=h and x=iPart(x) z+1 > z If x*(x+1)/2=i and x=iPart(x) z+1 > z If x*(x+1)/2=j and x=iPart(x) z+1 > z If x*(x+1)/2=k and x=iPart(x) z+1 > z If x*(x+1)/2=l and x=iPart(x) z+1 > z If x*(x+1)/2=m and x=iPart(x) z+1 > z If x*(x+1)/2=n and x=iPart(x) z+1 > z If x*(x+1)/2=p and x=iPart(x) z+1 > z If z = b Then a+b+c+d+e+f+g+h+i+j+k+l+m+n+p > s 0 > z For t, 1, iPart([math]\sqrt(s)[/math]), 1 If s/t=iPart(s/t) r+1 > r EndFor If r=i Then Disp a, b, c Pause Disp d, e, f Pause Disp g, h, i Pause Disp j, k, l Pause Disp m, n, p EndIf EndIf EndIf EndIf EndFor EndFor EndFor EndFor EndIf EndFor EndIf EndFor EndIf EndFor EndFor EndPrgm With this many loops I hope the calculator will be able to solve the quiz within a few hours? :p Last edited by Identity (20070923 17:10:50) #2 20070923 17:10:30
Re: Mean quiz :P...But my calculator doesn't seem to want to do it... when I run program it just says... #3 20130804 21:35:47
Re: Mean quiz :PHmm... How can this be solved? 'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.' 'God exists because Mathematics is consistent, and the devil exists because we cannot prove it' 'Who are you to judge everything?' Alokananda #4 20130804 23:34:20
Re: Mean quiz :PAh, I have a feeling phro would love this quiz! The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #5 20130815 00:34:27
Re: Mean quiz :PWhere is he? ঃ? 'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.' 'God exists because Mathematics is consistent, and the devil exists because we cannot prove it' 'Who are you to judge everything?' Alokananda #6 20130815 00:38:51
Re: Mean quiz :PDid anyone try the program? In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. 