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#1 2014-04-25 23:48:49

ManiticMath
Member
Registered: 2014-04-24
Posts: 29

The Unfortunate Adventurers

So here's a puzzle I made for you guys.

A group of 207 adventures group up to slay a dragon. They get the the mountain the dragon lives in and enter it. Unfortunately for them they all fall in to one of the dragons traps and are captured, and now weaponless.

The dragon likes to give large groups of people a puzzle. He gives 69 adventurers 2 bronze coins, He then gives 75 adventurers 3 silver coins, and gives the remaining 63 1 gold coin each. The dragon says that if everyone has the same value of coins in their hands when he comes back, they can all leave.

Now, It takes 3 bronze coins to equal a silver coin,and 4 silver coins to equal a gold coin.

The dragon comes back within five minutes. All the adventurers make it out alive. How did they do it?

Last edited by ManiticMath (2014-04-25 23:53:10)


When ever I see a brand new new math problem, I want to solve it. Then I want to burn it. Then I want to rebuild it in a new, more streamlined way.

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#2 2014-04-25 23:54:09

ManiticMath
Member
Registered: 2014-04-24
Posts: 29

Re: The Unfortunate Adventurers

Have fun with this one. I'm working on a few more puzzles.


When ever I see a brand new new math problem, I want to solve it. Then I want to burn it. Then I want to rebuild it in a new, more streamlined way.

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#3 2014-04-27 01:24:25

phrontister
Real Member
From: The Land of Tomorrow
Registered: 2009-07-12
Posts: 4,810

Re: The Unfortunate Adventurers

Hi ManiticMath,


"The good news about computers is that they do what you tell them to do. The bad news is that they do what you tell them to do." - Ted Nelson

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#4 2014-04-27 01:37:01

ShivamS
Member
Registered: 2011-02-07
Posts: 3,648

Re: The Unfortunate Adventurers

Last edited by ShivamS (2014-04-27 01:37:44)

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