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Ok, so I really need help with this one;
I need to show that y=x * lnx is a solution to the differentialequation y'-(y/x)-1=0
Any help would be really appreciated!
Integrating both sides,
logy=log(x-1).
Thats what I get
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Integrating both sides,
logy=log(x-1).
Thats what I get
I'm rather unfamiliar with these concepts. (Beginner) What does dx stand for?
And how did you integrate the sides? Is there a formula for this? For future reference.
X'(y-Xβ)=0
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What about
y=xlnx
y'=lnx+1
y'-y/x-1 -> lnx+1-xlnx/x-1 =lnx+1-lnx-1=0?
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