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Imagine the exam scores of a class of 10 students. Make three very different distributions that all have a mean of 80. ?? help
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I'm not going to solve this for you because it's fairly easy, but I'll tell you how to solve it.
First off - what is the (arithmetic) mean? Basicly it is when you take a number of observations(in this case exam scores), add them up and divide by the total amount of numbers.
Instead of 10 students, imaginge 3 students - yet the mean remains the same. So, what do we know?
There are 3 students.
The mean score is 80.
Where do we go from here? Well, the obvious solution is:
I don't know if any of this will make sense to you, but I'll write it anyway. It's just another way of showing what the mean is. If you understand this, however, you prolly know your mean. Anyway Here it goes:
First off, the x with a bar over it's head(x bar) is the mean of the set X with n elements(in your case n is 10 and "x bar" is 80)
If you consider my example with 60+80+100, it would look like this:
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