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#1 2016-05-21 17:01:34

pavya1
Guest

help me pleasee.....poison distribution

Aeroplanes arrive at airport at the average rate of 10 per hour. Air traffic controllers can safely handle a maximum of 15 planes per hour. Assume that the planes arrive randomly and independently and letP(x=j)=Aj=e^-10 (10)^j / j!... What is the probability that airport safely is jeopardized?

#2 2016-05-21 19:27:16

Bob
Administrator
Registered: 2010-06-20
Posts: 10,155

Re: help me pleasee.....poison distribution

hi pavya1

You need to calculate P(0), P(1) .... P(15) using the formula and add these up.  That's the probability of safety, so then do (1 minus that value) to get the probability of jeopardy.

Bob


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob smile

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#3 2016-05-21 19:59:52

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: help me pleasee.....poison distribution

Hi pavya1;

Using the Poisson distribution with mean = 10 you should get a probability of about 0.04874


In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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