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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 23,044

Hi;

611. Find the area of the quadrilateral, the coordinates of whose vertices are (3,-2), (5,4), (7,-6), and (-5,-4).

It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 23,044

Hi;

The solution 611 is correct. Neat work, bobbym!

612. If A(-3,5), B(-2,-7), C(1,-8), and D(6,3) are the vertices of a quadrilateral ABCD, find its area.

It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 23,044

Hi;

The solution 612 is correct. Excellent, bobbym!

613. Find the area of parallelogram ABCD if three of its vertices are A(2,4), B(2 + √3,5) and C(2,6).

It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 23,044

Hi;

The solution 613 is correct. Marvelous, bobbym!

614. Find the value(s) of k for which the points (3k - 1,k - 2), (k,k - 7) and (k - 1,-k - 2) are collinear.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 23,044

Hi;

The solution 614 is correct. Excellent, bobbym!

615. (i) Solve :

x + 2y + 2z = 11, 2x + y + z = 7, 3x + 4y + z = 14.

615. (ii) Solve :

x + 2y + z = 7, x + 3z = 11, 2x - 3y = 1.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 23,044

Hi;

The solution 615 (two parts) are correct. Neat work, bobbym!

616. (i) Solve : 2x - y = 4, y - z = 6, x - z = 10.

616. (ii) Solve : 3x - 4y = 6z - 16, 4x - y - z = 5, x = 3y + 2(z - 1).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 23,044

Hi;

The solution 616 (two parts) are correct. Excellent, bobbym!

617. If the points A(-1,-4), B(b,c) and C(5,-1) are collinear and 2b + c = 4, find the values of b and c.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 23,044

Hi;

The solution 617 is correct. Marvelous, bobbym!

618. Find the Greatest Common Divisor of

and .Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 23,044

Hi;

The solution 618 is correct. Splendid, bobbym!

619. Evaluate:

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 23,044

Hi;

The solution 619 is correct. Keep it up, bobbym!

620. Simplify:

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 23,044

Hi;

The solution 620 is correct. Splendid, bobbym!

621. Simplify:

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 23,044

Hi;

The solution 621 is correct. Excellent, bobbym!

622. Evaluate:

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 23,044

Hi;

The solution 622 is correct. Keep it up, bobbym!

623. Find the area of the following quadrilateral whose vertices are (6,1), (5,-6), (2,2), and (4,5).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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