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**Emma22****Guest**

Hi, I'm having trouble with applying initial data to a partial differential equation I've solved.

The general solution obtained is u(x,t) =F(x^2-t^2*exp(u)) and the initial condition is u(x,0)=2ln(x)

What I tired was plugging in the data to the general solution to get:

2ln(x) = F(x^2)

From there i let x^2 = z and hence x=sqrt(z), which gives me:

2*ln(sqrt(z)) = F(z)

and then I tried taking this and subbing it through to the original solution I had, which gives:

u(x,t) = 2*ln(sqrt(x^2-t^2 *exp(U))

The solution to the problem is u(x,t) = ln((x^2)/(1+t^2)), was wondering if anyone could help point out what i did wrong

Hi Emma22,

Welcome to the forum. Have you considered registering an account with us?

Emma22 wrote:

What is here? (You have later called this .)
The general solution obtained is u(x,t) =F(x^2-t^2*exp(

u)) and the initial condition is u(x,0)=2ln(x)

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**Grantingriver****Member**- Registered: 2016-02-01
- Posts: 101

Hi Emman22, the solution is as follow:

and hence

which is the required solution. Your solution is also correct, but it required some manipulation to reach the desired form.

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