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**Knewlogik****Member**- Registered: 2020-05-11
- Posts: 22

What would the formula look like 4 a series that starts at 0 then add any number but in digit root forum then add the previec e answe only after changing it to Dr

r?example: (0+1=1,1+1=2,3+2=5,5+2=7,7+2=9,9+2=11

n¹+n²=n³,n²+n³=n⁴,n³+n⁴=n5........but on n8 we get 2 digit number (11) and we need to make it in digit root fourum (2)?????

*Last edited by Knewlogik (2021-02-22 14:24:36)*

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**Bob****Administrator**- Registered: 2010-06-20
- Posts: 8,953

hi Knewlogik

I'm really not understanding what this is about at all.

Do you mean digital root form ?

Example of digital root form:

199

1+9+9 = 19

1+9 = 10

1 + 0 = 1

So 1 is the digital root of 199.

Would you provide three more examples of sequences, so I can follow what the 'rule' is.

Thanks,

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Sometimes I deliberately make mistakes, just to test you! …………….Bob

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**Knewlogik****Member**- Registered: 2020-05-11
- Posts: 22

1+1=2

1+2=3

2+3=5

3+5=8

5+8=13/(1+3=4)

8+4=12/(1+2=3)

4+3=7

3+7=10/(1+0=1)

7+1=8

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**irspow****Member**- Registered: 2005-11-24
- Posts: 855

I followed it to see if it formed a repeating pattern and it is indeed a repeating sequence.

1,1,2,3,5,8,4,3,7,1,8,9,8,8,7,6,4,1,5,6,2,8,1,9 and then repeats.

You could brute force a 24th order equation to spit out the sequence but that would certainly be extremely tedious unless you hand it over to a computer. What significance is the sequence supposed to have?

I am at an age where I have forgotten more than I remember, but I still pretend to know it all.

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**Knewlogik****Member**- Registered: 2020-05-11
- Posts: 22

What is a 24th order equation?

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**Knewlogik****Member**- Registered: 2020-05-11
- Posts: 22

How do u right this in a formula form

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**irspow****Member**- Registered: 2005-11-24
- Posts: 855

A 24th order equation would take the form of ax^24+bx^23+cx^22+...zx. I mentioned it jokingly because the expression would be more complex than than the sequence itself. Also, since there is never a constant rate of change, even if you worked out that 24th order equation it would be useless beyond the 24th term. It would ‘break’ if used beyond the 24th term and thus would not create a repeating sequence. Since it is repeating it could be expressed as a fraction of integers, but this too is more complex than the sequence itself.

This is all the long-winded way of saying that there is no ‘formula’ that would give you the unit digit of the sequence by the term number. The best you could do is to have a computer crunch the numbers as we did to find the repeating sequence or more efficiently create a list (the repeating numbers of the sequence) and have the script select the nth term in the sequence.

I am at an age where I have forgotten more than I remember, but I still pretend to know it all.

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