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Yeah i'm having trouble remembering how to solve a exponent that is a negative and it is a fraction
ex. 9^-2/3 i know to put that under one as a fraction and the exponent becomes a positive so what do i do after that???????
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Hi mcart1gd,
Your problem is 9^ -2/3
= 1/ 9^(2/3) {Since x^-1 = 1/x}
= 1/81^(1/3)
So, the answer is the reciprocal of the cube root of 81.
Let me explain this with a simple example.
Consider 8^-2/3
= 1/8 (2/3)
= 1/ 64^(1/3)
= 1/4.
Hope you will understand.
Letter, number, arts and science
of living kinds, both are the eyes.
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Correct. Also see Exponents and Fractional Exponents
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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