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Hi,
Could anyone help with this:
Show that:
can be expressed as:
Thanks,
Mitch.
Last edited by gnitsuk (2006-08-29 01:38:28)
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Mitch, did you ever get an answer for this?
igloo myrtilles fourmis
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Hi,
No, I never got a reply to this or the subsequent one. Apart from a triple angle substitution and lots of algebra, I have no other ideas. The context of the problem is in a caculus text. I have arrived at the first formula and the answer given is in the second form. Given that it's a calculus question I would be suprised if one had to do lots af algebra at the end just to get into the form given - still, it's possible. Moreover. I was looking for a quicker method which I had missed.
Thanks,
Mitch.
Last edited by gnitsuk (2006-09-03 21:57:08)
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I've got some progress, and I wish you can put the finishing touch.
Firstly, notice 1-cos(2t)=2sin[sup]2[/sup](t)
Thus you get the chance of cancelling sin[sup]2[/sup](t) in the denominator and the numerator together.
And the crucial step is to express the denominator as some product with sin[sup]2[/sup](t).
the second and the last part are ok, but what about the first one?
use a[sup]3[/sup]-b[sup]3[/sup]=...
sin(3t)-sin(t)=2sin(t)cos(2t) -- one sin(t)
sin(3t)^2=?
Use Euler formula and find sin(3t) expressed as trig of t. In this way you can complete another sin(t)
sin(3t)=3cos[sup]2[/sup](t)sin(t)-sin[sup]3[/sup](t)
Last edited by George,Y (2006-10-01 01:04:09)
X'(y-Xβ)=0
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Hi, thanks for your help.
I finally did it this way:
Result (1):
So from:
we can replace
in the numerator with
and
in the denominator with our result (1) to get:Now divide numerator and denominator by
to giveEquation (1):
Result (2)
Result (3)
Now we can substitute Results (2) and (3) into the denominator of Equation (1) to give:
Divide numerator and denominator by 8 giving:
Call this Equation (2)
Result (4):
Substitute this into equation (2) to finally give:
Last edited by gnitsuk (2006-10-02 03:21:30)
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