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#1 2024-03-23 05:27:12

nycguitarguy
Member
Registered: 2024-02-24
Posts: 493

Maximum Average Cost

The maximum average cost per hour in dollars, C bar, of producing x riding lawn mowers can be modeled by the function

C bar = 0.3x^2 + 21x - 251 + (2500/x)

A. Graph C bar = C bar (x)

B. Determine the number of riding lawn mowers to produce in order to minimize average cost.

C. What is the minimum average cost?


Note:

1. There is a bar over C. This is why I say C bar here.

2. Do not use calculus.

3. Can someone graph this function for me here?

4. I seek the steps for B and C.

Last edited by nycguitarguy (2024-03-23 05:28:58)

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#2 2024-03-23 05:54:10

Bob
Administrator
Registered: 2010-06-20
Posts: 10,172

Re: Maximum Average Cost

Z1NtBFh.png

You can see the minimum. B is just the x value at that point and y is the cost at the minimum.

Bob


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob smile

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#3 2024-03-24 10:07:46

nycguitarguy
Member
Registered: 2024-02-24
Posts: 493

Re: Maximum Average Cost

Bob wrote:

https://i.imgur.com/Z1NtBFh.png

You can see the minimum. B is just the x value at that point and y is the cost at the minimum.

Bob

The say B = 10 riding lawn mowers per hour.

I say C = y coordinate at the point that = 10 for x.
I say about $239....

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