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Let f(x) = sqrt{ x } be the square root function.
1. Why is the function neither even or odd?
If I let x be -x, I get sqrt{-x}. I don't understand why the square root function is neither even or odd.
2. Why does the function have an absolute minimum of 0 at x = 0?
I say because the graph of f(x) = sqrt{x} begins to rise from the origin where x = 0.
You say?
The Rapture is the central event in biblical prophecy. The greatest truth about the Rapture is not its timing but it's reality. The Rapture will be the great disappearance.
Dr. David Jeremiah
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To test a function with respect to odd/even you have to be able to try -x in place of x. But the function isn't defined for negatives so you cannot do the test. Or, to investigate by inspecting the graph: has it got reflective symmetry in the y axis or rotational symmetry around (0,0) ? No because there are no negtaive points on the curve.
Your answer for part 2 is correct.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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To test a function with respect to odd/even you have to be able to try -x in place of x. But the function isn't defined for negatives so you cannot do the test. Or, to investigate by inspecting the graph: has it got reflective symmetry in the y axis or rotational symmetry around (0,0) ? No because there are no negtaive points on the curve.
Your answer for part 2 is correct.
Bob
Perfect. Thanks.
The Rapture is the central event in biblical prophecy. The greatest truth about the Rapture is not its timing but it's reality. The Rapture will be the great disappearance.
Dr. David Jeremiah
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Pages: 1