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#1 2007-01-03 12:46:57

Liz
Guest

please help! i would appreciate it soooo much!

37. Can you find values for a and k so that the graphs of y= |x+a|+k and y=x^2 intersect at exactly one point?

42.graph the equation or inequality
y=  1
         x-2 
         
         

^whats the slope and intercepts? im not sure on how to find them?

and lastly

47.you are given a table of values
x=84 y=8
x=36 y=6
x=16  y=4
x=4  y=2
x=0  y=0
a)even though y-values decrease by 2, the graph for this data is not a line with slope -2. Why not?
b)Write and equation that relates x and y.
c)The pattern suggests that the next pair in the table should be (-4, -2). Does this point fit your equation from part b?

#2 2007-01-03 16:49:58

pi man
Member
Registered: 2006-07-06
Posts: 251

Re: please help! i would appreciate it soooo much!

I'll take on the last one..

47.   Are you sure the first set of numbers isn't supposed to be x=64, y=8?  If so then the an equation which contains those points would be x = y^2.
   a) The graph is not a line (y=mx+b) but rather a curve.    Only lines have slopes.
   b) x = y^2   (assuming you made a type on the first set of numbers)
   c) No.  It would be (4, -2) since (-2)^2 = 4

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#3 2007-01-03 17:06:05

pi man
Member
Registered: 2006-07-06
Posts: 251

Re: please help! i would appreciate it soooo much!

42.   The equation is not a line so it doesn't have a slope.  To figure out the intercepts, you plug in 0 for one of the variables and compute the other. 

There is no value of x where y = 0.   So there isn't an x intercept.  The function is undefined for x=2 since you would be dividing by 0.

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