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how would you graph or maybe I should say how do you find more points on the y-intercept if the info you have is slope -2; y-intercept (0,4) in order to graph?
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If the slope is -2 and the y-intercept is (0,4), then the equation of the line is y=-2x+4.
From there, to find more co-ordinates you just need to pick a value for x, and substitute that into the equation to find what y will be.
For x=3: y = -2*3+4 = -6+4 = -2. ∴ (3,-2)
For x=-1: y = -2*-1+4 = 2+4 = 6. ∴ (-1,6)
And so on.
Why did the vector cross the road?
It wanted to be normal.
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To graph, first plot the point (0,4). The slope is -2. The slope is "rise over run" so the denominator is the change in x and the numerator is the change in y. A slope of -2 is the same as -2 / 1. If x changes by 1 (the denominator), y changes by -2 (the numerator).
Let's find another point on this line by increasing X by 1. That gives us 1 (0+1). Everytime X increases by 1, y decrease by 2 (slope is -2). So the y value would be 2 (4-2). Plot the point (1,2) and draw a line through (0,4) and (1,2) and you're done.
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thanks alot so if slope is 5 and y-intercept: (0,-2) y=5x -(-2); so I graph (0,-2) then slope is rise over run slope of 5 =5/1 so if x changes by 1 then y would change by 5 so y value would be 5(5-2) plot the point of (1,3) am I on the right track or did I not get something.
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You're on the right track. And to prove to yourself that it's right, plug your new point of (1,3) into your equation. Your equation should be y = 5x - 2 rather than y= 5x - (-2). Plug in 1 for x and 3 for y:
3 = 5(1) - 2
3=3
Success.
Last edited by pi man (2007-01-22 07:27:46)
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