You are not logged in.
Pages: 1
Here it is... thanks in advance
Let D be the midpoint of the base (i.e. CD is the common side of the two squares).
Then triangle ADB is an isosceles right-angled triangle.
∴ Angle ABC = 60° − 45°
= 15°
Offline
Thank you very much! ^_^ I should have got that!!! lol
Youre welcome.
Offline
Pages: 1