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find x15 in the binomial expansion of (2x-5/4x)20.
There is no term in x[sup]15[/sup]. All the terms in the binomial expansion of that expression involve only even powers of x.
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Wouldn't that just mean that the term is 0x^15?
Why did the vector cross the road?
It wanted to be normal.
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Wouldn't that just mean that the term is 0x^15?
Yes!
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