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#1 2007-08-23 22:49:19

Will Partridge
Guest

Tricky equation to solve..

Hello, I have an equation that has stumped me. I need to put it into the form 'g = ...'

Any help appreciated:

1000g^2p - 10g^2pq - 50000g - 140000gn - 300gp - 3gpq = 1000(h + i)

p,q,n,h and i are all constants.

Cheers!

Will

#2 2007-08-23 22:52:38

Will Partridge
Guest

Re: Tricky equation to solve..

Oh, and just to clarify the squared parts are:

1000 * (g * g) * p

and

10 * (g * g) * p * q


thanks

#3 2007-08-23 23:32:40

HallsofIvy
Guest

Re: Tricky equation to solve..

Will Partridge wrote:

Hello, I have an equation that has stumped me. I need to put it into the form 'g = ...'

Any help appreciated:

1000g^2p - 10g^2pq - 50000g - 140000gn - 300gp - 3gpq = 1000(h + i)

p,q,n,h and i are all constants.

Cheers!

Will

Okay, that is (1000p-10pq)g^2- (50000+140000n+ 300p- 3pq)g- 1000(h+i)= 0, a quadratic equation.  Use the quadratic formula.

#4 2007-08-23 23:56:09

MathsIsFun
Administrator
Registered: 2005-01-21
Posts: 7,711

Re: Tricky equation to solve..

Quadratic Equation

Using HallsofIvy's equation:

a = (1000p-10pq)
b = (50000+140000n+ 300p- 3pq)
c = 1000(h+i)

Pop those into the Quadratic Formula, simplify if possible, and you are done smile


"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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