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This probability question was in an example in my textbook, but it wasn't explained clearly so I was wondering if anyone could explain the steps! Thanks in advance!
Compute P(X>10) when X has a geometric distribution with parameter p.
In a geometric distribution, p is the probability of success and (1−p) the probability of failure of each trial of an experiment. P(X>10) is the probability that more than 10 trials are needed to succeed in the experiment. This is, in other words, the probability that the first 10 trials end in failure which is (1−p)[sup]10[/sup].
The formal calculation is as follows.
Last edited by JaneFairfax (2007-09-26 00:53:31)
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