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solve in R
Last edited by tony123 (2007-10-01 21:46:39)
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I don't know how to do it with legit pure math, but one answer is (4,9). ![]()
igloo myrtilles fourmis
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(4,9).is the only answer but how
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Yes Your Right About The Answer Being (4,9) But I Also Do Not Know How Its (4,9).
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Rearrange it into 9(4/a + a) + (9/b + b) = 42, where a = √x and b = √y.
Now find min(4/a + a). You do this by differentiating and equating to 0.
(4/a+a)' = -4/a² + 1 = 0
-4/a² = -1
4 = a²
a = ±2.
But as a = √x and you can't get (real) negative roots, then a=2 (and thus x=4) is the minimising value.
For this, 9(4/a + a) = 36.
Following a similar procedure for the other half gives that min(9/b + b) = 6, when b=3 (and so y=9).
Adding these minimum values produces 42. As it's a minimum and there was only one solution do the differential equation in both cases, then (4,9) is the only solution that works. Any other (x,y) will give a greater answer.
Why did the vector cross the road?
It wanted to be normal.
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