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sum Series
1/(log 2) + 1/(log 2)(log 3) + 1/(log 2)(log 3)(log 4) + ...
1/(sin²1)² + 1/(sin²1+sin²2)² + 1/(sin²1+sin²2+sin²3)² + 1/(sin²1+sin²2+sin²3+sin²4)² + .
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I found where you took these problems from: http://www.contestcen.com/conv.htm
The instructions say that we only need to determine whether the series converge or diverge; it doesnt say that we have to evaluate the sum if the series is convergent. Also, the instructions say that the log is natural logarithm. If thats the case, then 1⁄(log(3)) < 1 and the first one becomes a piece of cake.
So the sequence of partial sums is increasing and bounded above hence the series is convergent! If its not required to find what it converges to, then thats it. Thats the first problem solved.
Second problem umm
BTW, I think this is the last of Tonys threads in this forum that has (prior to this post) not had any replies. If there are any more unanswered threads by Tony, Id like to find them.
Last edited by JaneFairfax (2007-12-19 23:34:17)
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