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#1 2008-02-18 23:04:17

Peaches47
Member
Registered: 2008-02-17
Posts: 13

Powers of Trig... 2nd Approach

eekOk Ok... I have to try this one again.  I have looked every where and re-read the paragraph on the powers of trig functions, nothing was revealing (to me any way).   Here's my repost to my orginal.dunno

Help me guys  there is got to be some soultion on how to work this out. 

Mathsyperson:  thanks for the laugh I agree the book shows examples of the Trig functions with powers .  Then ask to figure out  cos 4x however it does proved multiple choice answers of:
3-4 cos 2x + 4x / 8
or
2-4 cos 2x + 4x /8
or
3-2 cos 2x + 4x /8
or
3+4 cos 2x + 4x /8

I tired a little backwards thinking but still can't figure it out and more feed back you can add is welcome and I checked again,  unless its a typo  it does say  "cos 4x"


Struggling Middle Aged Math Student

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#2 2008-02-19 12:32:51

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

Re: Powers of Trig... 2nd Approach

What exactly is the question?  If it's in your first post, I don't understand.


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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#3 2008-02-19 12:52:19

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: Powers of Trig... 2nd Approach


Why did the vector cross the road?
It wanted to be normal.

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