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#1 2008-02-27 22:18:44

mathacc
Guest

Matrix X'X=A is given <- how to get X?

Sry too simple question probably.
But I have the matrix X'X (=A) given, and have to find X. X is symmetric. Is there an easy trick? thanks

#2 2008-02-28 00:25:54

JaneFairfax
Member
Registered: 2007-02-23
Posts: 6,868

Re: Matrix X'X=A is given <- how to get X?

What is X′? Is it the transpose of X? If it is, then you should know that if X is symmetric, its transpose is equal to X itself.

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#3 2008-02-28 09:30:24

mathacc
Guest

Re: Matrix X'X=A is given <- how to get X?

hi yes thats clear.
X' is the transpose of X.
but (X'X) is given. how to get the single X or X', respectively?

thanks

#4 2008-02-28 10:17:00

JaneFairfax
Member
Registered: 2007-02-23
Posts: 6,868

Re: Matrix X'X=A is given <- how to get X?

What’s the size of X? If X is only 2×2, you can let

and try and solve for X. If X is a bigger matrix, well … it’s a bit more complicated. dizzy

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#5 2008-02-28 17:10:28

mathacc
Guest

Re: Matrix X'X=A is given <- how to get X?

it's actually a 4x4 matrix smile

#6 2008-02-29 01:16:37

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: Matrix X'X=A is given <- how to get X?

What's A? It's a hard problem to solve in general, but if A is nice we might have some shortcuts.
Especially if it's got a lot of 0's.


Why did the vector cross the road?
It wanted to be normal.

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#7 2010-09-10 15:32:35

George,Y
Member
Registered: 2006-03-12
Posts: 1,379

Re: Matrix X'X=A is given <- how to get X?

I guess you should take primary manipulation both horizontally and vertically until you reduce it to simple I matrix, that is
A=P[sub]n[/sub]...P[sub]3[/sub]P[sub]2[/sub]P[sub]1[/sub]IP'[sub]1[/sub]P'[sub]2[/sub]P'[sub]3[/sub]...P'[sub]n[/sub]


X'(y-Xβ)=0

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