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using the formula
X = -b ± √ b² - ac
2a
solve the equation 5x² - 9x + 2 = 0
would be great help if some one could show me a step by step way of working this out.
Thanks karl
using the formula
X = -b ± √ b² - ac
______________
2a
solve the equation 5x² - 9x + 2 = 0
would be great help if some one could show me a step by step way of working this out.
Thanks karl
The formula you have is the solution to ax² + bx + c = 0.
In your case, a=5, b=-9, c=2. Put those numbers into the formula to get out your answer.
Why did the vector cross the road?
It wanted to be normal.
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so it would then be writen
x = -9 ± √ -9² - 5 - 2
____________________
2 X 5
so do i do the hole sum adding the -9 to the square routed section to get one answer
then do it all again taking the -9 from the square routed section
to give the two possible answers ??
thanks for the help karl
Kind of, but it's the square rooted bit that you either add or take away. The -9 is always there.
Also, you've got a mistake in your quadratic formula (sorry for not noticing this earlier).
It should be:
Note the 4ac in the square root, instead of just ac.
Why did the vector cross the road?
It wanted to be normal.
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