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how would you solve
log(2x+2) + log x - log(12)=0
and
log½ gives the same answer as -log2
true or false?
explain why?
any help would be much appreciated!!!
Last edited by sachik (2008-05-17 20:03:10)
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In both questions, use that logx+logy=logxy, logx-logy=log(x/y)
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Using the rules:
You get:
Using
, orBUT! x cannot equal -3, because if you plug -3 back into the equation, you will get the log of a negative number. You cannot have the log of a negative number, so x = 2 is the only solution.
For your second question,
But
(anything to the power of 0 is 1)Last edited by Identity (2008-05-17 20:51:11)
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Thanks a lot, everything makes better sense now
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