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Hi Everyone,
Always making small mistakes in my calculation but unfortunately that make me loose points:(
I would like to know if I didn't make any mistake on that question:
       This question concerns the function 
                f(x)= x^3 +3x^2 − 9x+15. 
Find the stationary points of this function:
     The derivative of the polynomial function
         f(x) = x^3 + 3x^2  9x + 15
        f (x) = (3x^2) + 3(2x)  9(1)
                = 3x^2 + 6x  9
                = 3(x^2 + 2x  3)
      The equation f (x) = 0 is equivalent to x^2+2x-3 = 0;
      That is, (x+3)(x-1) = 0
      Which give the stationary points:
      X= -3 and x= 1
Thanks for your help:)
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correct., although to find the stationary points, you should then substitue those two values of x to get 2 x,y pairs
The Beginning Of All Things To End.
The End Of All Things To Come.
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Thanks luca-deltodesco for your help:):D
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