Math Is Fun Forum

My problem is with the fact that x^i is ith root (1/x) is (x^-i)^(1/i)=(x^-i)^-i*=(x^-1)**=(1/x)
when this is done twice, we get something like x=x^-1
x=1/x
This is only true for x = {1,-1}

This makes NO sense whatsoever.

*1/(a+bi)=a/(a^2 + b^2) - (b/(a^2 + b^2))i
**(a^b)^c=a^(b*c)

(Got rid of those pesky smilies)