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Soo... let the people who have a problem with the idea cometh here! Cause I just figured it out, and I like to hear new ideas.
Oh cool, I just turned into a Member!
sorry, off topic.
Yes. I just got a glimpse of (cue mystical music) The world of MAATH!
ok.
i thought meant multiply.
So all that I had the problem with was the wording of the problem on the site. I say yes.
Like (5 times 1= 5) and (5 times 0.999... = 5)
What do you mean?
the period after the 5 is a sentence stopper period.
Thats what I wrote, right?!?!
And that means that 0.999... has the same properties as 1.
Like 50.999... = 5.
So we're sure about that, right?
Yeah, I have never disagreed with that.
I know that 1 can be representated more than once, but what I am trying to figure out is if 0.999... written in standard form is the same as 1 written in standard form. Now I am 0.6 leaning toward Yes.But every so often my brain goes back to no.
And talking about brainpower, I am higher then 5th grade.
Agree.
Not 3rd grade little, but not College big.
I put "1234" and it showed all these complicated things, it couldnt just say Count to 4 from 1.
There IS
1.0
01
1 1
2-1
x^0
etc...
I AM going both ways on this subject.
I'm just a little kid, don't confuse me too much!
My personal view- but I do not like the wording.
I (thought) it's like the "proof" of 1=2. There has to be a hidden mistake.
The problem( copied and pasted )
~~~~~~~~~~~~~~~~~
Let X = 0.999...
Then 10X = 9.999...
Subtract X from each side to give us:
9X = 9.999... - X
but we know that X is 0.999..., so:
9X = 9.999... - 0.999...
or: 9X = 9
Divide both sides by 9:
X = 1
But hang on a moment I thought we said X was equal to 0.999... ?
Yes, it does, but from our calculations X is also equal to 1. So:
X = 0.999... = 1
Therefore 0.999... = 1
~~~~~~~~~~~~~~~~~~
Common Sense: The integer 1 has a 1 in the ones place, and 0.999... has a zero.
But, (oh crack, I just got confused!) 1/3 = 0.333... and 1/3 3 =3/3=1, and 0.333... 3 =0.999...
so 0.999 would equal (1)! ( put parenthesis so not to be mistaken for 1!)
I need some diffrent opinions...
EDIT: I say yes now, thnx bobby!
Hi, I'm me!:) Call me Belle. I'm an advanced kid. Gimme a math problem, please. I'm a long time fan of Mathisfun.com, and only now got around to regestering here.
Soo... who are you?
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