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Ok so i have the next exercise.
I didn't had any problems solving a) and b)
What about c?
Can anyone tell me how to resolve it?
I googled it and found out that's Si(x)(whatever that is) and i don't know about what's that since i'm just last grade of high school.
Any help?
Indeed,good point you are right.
http://www.mathsisfun.com/data/function-grapher.php?func1=sqrt%28x%29&func2=2
That would be quite hard.
I know the problem is to prove that x does not have roots on (-1,0) because it's easy to see on the other cases.Ideas?
You got it wrong.
In my opinion the first one is always positive for any x real but i don't really know how to prove it.
Not any opinions/ideas yet?
It's N* sorry math. I don't really know how to write N* or R*+.How you do that?
Done yeah cool now i found out how it works. hehe
Hey guys.I have a little question or just a personal wonder about them.
integral of 1/(sin^4x+cos^4x)dx
f:[0,3]->R f(x)=max{3-x,2x+[x]} . Show that f is integrable on[0,3] and calculated integral of f(x)
integral of sqrt(x-x^2)
ok i understand....thank you!
integral of 1/(x^4+x^2+1):D:D
It means that f(x) =y,y is part of R.
But it's very helpful,i like it.Thank you very much ^_^.
For a>=1 there are real solutions.For a<1 there are not.That function grapher is for R not for C.
x1 are the solutions to the ecuation like...
f(x1)=0,f(x2)=0,f(x3)=0,f(x4)=0;
Sorry that's how i know to note them.
Yes i had the same ecuations,but i've been tired and just couldn't focus yesterday.Got them now thank you.
By the way,any clues on 1st problem?
Ok i got those ecuations either.W/E i'm stupid.Thank you.
Hi;
f(1)=9
f(2)=-5
f(3)=0
f(4)=35
Could you describe your solution step by step please? For f(1)=8 not 9 sorry.
Ok guys a second problem
f(1)=8
f(2)=-5
f(3)=0
f(4)=35
f=?
The thing is i know how to solve the problem but i cannot really solve the system.
f(3)=0 -> x1=3 solution ->f = (X-3)(aX^2+bX+c)==>
==>f=aX^3+(b-3a)X^2+(c-3b)X-3c
so f(3)=0 ==>-3c=0 =>c=0
f(1)=8 ==> a+b=-4
f(2)=-5 ==>-4a-2b=-5==>4a+2b=5
f(4)=35 ==> 16a+4b=35
Can anyone solve the system or at least tell me where i'm wrong ? I'm getting very mad here.
Also you could use Viette's formulas and the fact that f=(X-x1)(X-x2)(X-x3) where x1,x2,x3 are roots of the ecuation.
Hello guys long time no see,got a new exercise:
On R[X] f=X^4-aX^3-aX+1
Proove that if |a|<1 then |x1|=|x2|=|x3|=|x4|=1;
Good luck.
How do you write mathematical here?
I mean with all the symbols and etc.
Interesting proof,i thought of a different one.