Math Is Fun Forum
You are not logged in.
- Topics: Active | Unanswered
#1 Re: This is Cool » A Point Cannot Be Measured » 2024-05-23 23:35:10
AnthonyRBrown wrote:Ok do you want me to measure the size of the point? or measure where the point is on the paper?
I can measure where the point is on the paper with a simple ruler. Measure the circumference, radius and diameter of the DOT, you know, the DOT on your paper. Find the area of the DOT, the DOT itself.
OK! There are two solutions to this 
Solution (1) If you use a felt tip pen as an example to make a point on a piece of paper,then it can be measured because it exists!
Solution (2) If you use a reference point as a point,then it cannot be measured because it does not exist!
A.R.B
#2 Re: This is Cool » A Point Cannot Be Measured » 2024-05-22 01:14:08
Ok do you want me to measure the size of the point? or measure where the point is on the paper?
#3 Re: This is Cool » A Point Cannot Be Measured » 2024-05-21 20:44:43
AnthonyRBrown wrote:mathxyz wrote:A point cannot be measured is a definition in Geometry that must be accepted as truth.
There is no such thing as "must be accepted"! where I come from,for me that is like a Red flag to a Bull
My whole life has been driven by proving that wrong! and many others who naturally think outside the box,can you imagine how many great inventions,acheivments,scientific breakthroughs,etc. that would have been missed if all.those people took notice of the "must be accepted"
Perfect. Now you can prove mathematically why a point has no measure. We are all waiting for this great mathematical feat.
mathxyz I think you have misunderstood the type of person I am,I am not driven by "trying to prove mathematically why a point has no measure."
I am driven by proving mathematically why a point has a measure!
So the first questions for you is...Can the point you are talking about be seen? or is the point you are talking about an imaginary point?
#4 Re: This is Cool » A Point Cannot Be Measured » 2024-05-21 17:38:30
AnthonyRBrown wrote:Ok so I have an idea on how a point can be measured...
So we attached the amount of ink that was going to be used to write a point,to the end of a needle then we drop the ink onto an Atomic weighing scale,this should give us an accurate measurment of a point!
A point cannot be measured is a definition in Geometry that must be accepted as truth.
There is no such thing as "must be accepted"! where I come from,for me that is like a Red flag to a Bull
My whole life has been driven by proving that wrong! and many others who naturally think outside the box,can you imagine how many great inventions,acheivments,scientific breakthroughs,etc. that would have been missed if all.those people took notice of the "must be accepted"
#6 Re: This is Cool » A Point Cannot Be Measured » 2024-05-21 04:57:28
Ok so I have an idea on how a point can be measured...
So we attached the amount of ink that was going to be used to write a point,to the end of a needle then we drop the ink onto an Atomic weighing scale,this should give us an accurate measurment of a point!
#7 Re: This is Cool » A Point Cannot Be Measured » 2024-05-20 22:05:54
KerimF wrote:mathxyz wrote:A point cannot be measured is found in most if not all geometry textbooks.
Sorry for not being clearer.
Can we see THE point as defined in Geometry? Of course, we can't point out to something and say this is THE point as it is defined in Geometry.
And isn't this unseen point very useful if it is included in some scientific studies? Of course, it is (to me in the least).I mean, this is the logical answer to those who insist that one 'should ignore' an idea (and its related studies) if it refers to something or entity that cannot be seen (dur to lack of complete definition, for example).
After all, we can't blame them. They surely didn't have the chance or the time to learn and use Geometry for example.What else in the world cannot be measured?
Love,Hope,Faith
If a point cannot be measured? then what's the point!
#8 Re: Puzzles and Games » The A.R.B Strongest Games Programs In The World! :) » 2024-05-12 21:39:55
The A.R.B Strongest Games Programs in the World!
https://www.youtube.com/watch?v=Xg36QswuC_U
#9 Re: This is Cool » Fermats Last Theorem Demonstration! by, Anthony.R.Brown (1998 Solved ) » 2024-05-08 20:38:24
Proving Fermat' s Last Theorem (almost) in just 2 minutes !
https://www.youtube.com/watch?v=EymVXkPWxyc
#10 Puzzles and Games » The A.R.B Strongest Games Programs In The World! :) » 2024-04-24 07:25:53
- AnthonyRBrown
- Replies: 1
For anyone interested in playing against AI games...
Below are my Big updates for my latest games programs 24.04.2024,they will be the last for some time!
THEARBTICTACTOEV3X3PROGRAM24042024
THEARBCONNECT4V7X6PROGRAM24042024
THEARBCONNECT4V8X8PROGRAM24042024
THEARBALL4CONNECT4V8X8PROGRAM24042024
The programs include all my latest AI innovations...
{ RISKY+ MODE } { TURBO LEARN! } { PERFECT-AI }
Download link below...
github.com/TARBCS/The-A.R.B-Strongest-Games-Programs-In-The-World
#11 Re: This is Cool » Fermats Last Theorem Demonstration! by, Anthony.R.Brown (1998 Solved ) » 2024-04-23 22:45:50
Truth will out.
#12 Re: This is Cool » Fermats Last Theorem Demonstration! by, Anthony.R.Brown (1998 Solved ) » 2024-04-23 15:47:14
2024-04-10 11:18:46
AnthonyRBrown
Posts: 46
The FLT Demonstration program I made was made FREE! on a budget! It satisfies to show the Three Patterns A,B,C for the accuracy of the program up to certain level.
Most people read all the threads,and then walk away!
#13 Re: This is Cool » Fermats Last Theorem Demonstration! by, Anthony.R.Brown (1998 Solved ) » 2024-04-23 05:13:50
It never gives up!
#14 Re: This is Cool » Fermats Last Theorem Demonstration! by, Anthony.R.Brown (1998 Solved ) » 2024-04-18 21:07:07
It's all a Mystery ? Like trying to get blood out of a stone!
#15 Re: This is Cool » Fermats Last Theorem Demonstration! by, Anthony.R.Brown (1998 Solved ) » 2024-04-12 03:39:19
Sorry but you cannot correct the Truth!
As far as you dropping out of this thread,you put yourself in it! the bed is made,now lay in it!
A.R.B
#16 Re: This is Cool » Fermats Last Theorem Demonstration! by, Anthony.R.Brown (1998 Solved ) » 2024-04-11 07:31:13
The reason my calculations are wrong? is because you keep making mistakes and putting forward the wrong information/numbers...
You put forward the wrong number below...
1234570577558058492212429272138645554498496 ?
And then said...
Sorry...grabbed the wrong number (careless!). Should've been 1234570577557885867934842042214716618784231
The biggest mistake you made is that you said...
the two numbers are from different groups of ten and are the first number in their group, and both groups satisfy the A,B,C Patterns)
So the first number in their group means for Pattern C DIVIDE COUNT = 1 and then the next DIVIDE COUNT'S to 10
And now you are giving a much higher DIVIDE COUNT 107276675808311 for the first ?
MY CUBE NUMBER PROGRAM! with the Patterns A,B,C Shows if a group of 10 numbers are Cube numbers! but it also shows all the Cube numbers from the first 10,for as far as it's possible to calculate,Which is where we can find out if a group of 10 numbers are cubes or not?
Below are the first 10 Cube numbers!...
CUBE = 1 : PATTERNA1 = 1 : PATTERNB7 = 7 : PATTERNC1 = 1 : COUNT = 1
CUBE = 8 : PATTERNA8 = 8 : PATTERNB9 = 19 : PATTERNC4 = 4 : COUNT = 2
CUBE = 27 : PATTERNA7 = 27 : PATTERNB7 = 37 : PATTERNC9 = 9 : COUNT = 3
CUBE = 64 : PATTERNA4 = 64 : PATTERNB1 = 61 : PATTERNC6 = 16 : COUNT = 4
CUBE = 125 : PATTERNA5 = 125 : PATTERNB1 = 91 : PATTERNC5 = 25 : COUNT = 5
CUBE = 216 : PATTERNA6 = 216 : PATTERNB7 = 127 : PATTERNC6 = 36 : COUNT = 6
CUBE = 343 : PATTERNA3 = 343 : PATTERNB9 = 169 : PATTERNC9 = 49 : COUNT = 7
CUBE = 512 : PATTERNA2 = 512 : PATTERNB7 = 217 : PATTERNC4 = 64 : COUNT = 8
CUBE = 729 : PATTERNA9 = 729 : PATTERNB1 = 271 : PATTERNC1 = 81 : COUNT = 9
CUBE = 1000 : PATTERNA0 = 0 : PATTERNB1 = 331 : PATTERNC0 = 100 : COUNT = 10
Below are your first 10 numbers!
If my 10 cube numbers before this show that your 10 numbers are not the next 10 in order? then they are not cube numbers...
1234570577558077903820610782563862681159521
1234578963300600764248728267290289327790208
1234587349091946113381524138491336181010667
1234595734932114188092585109001774777647104
1234604120821105225256417288321736157578125
1234612506758919461748446185293104905117056
1234620892745557134445016710775918384436823
1234629278781018480223393180324771169042432
1234637664865303735961759316865224665296089
1234646050998413138539218253370221930000000
If my 10 cube numbers after this show that your 10 numbers before my 10 are not in order then they are not cube numbers...
Below are your second 10 numbers!
If my 10 cube numbers before this show that your 10 numbers are not the next 10 in order? then they are not cube numbers...
1234570577557885867934842042214716618784231
1234570577557920392790359486912182296227328
1234570577557954917645876932253308028520297
1234570577557989442501394378238093815663144
1234570577558023967356911824866539657655875
1234570577558058492212429272138645554498496
1234570577558093017067946720054411506191013
1234570577558127541923464168613837512733432
1234570577558162066778981617816923574125759
1234570577558196591634499067663669690368000
If my 10 cube numbers after this show that your 10 numbers before my 10 are not in order then they are not cube numbers...
#17 Re: This is Cool » Fermats Last Theorem Demonstration! by, Anthony.R.Brown (1998 Solved ) » 2024-04-10 22:10:27
Your first (10) Numbers Pass as PATTERN (A) = 1,8,7,4,5,6,3,2,9,0 in brackets ()
123457057755807790382061078256386268115952(1)
123457896330060076424872826729028932779020(8)
123458734909194611338152413849133618101066(7)
123459573493211418809258510900177477764710(4)
123460412082110522525641728832173615757812(5)
123461250675891946174844618529310490511705(6)
123462089274555713444501671077591838443682(3)
123462927878101848022339318032477116904243(2)
123463766486530373596175931686522466529608(9)
123464605099841313853921825337022193000000(0)
Your Second (10) Numbers Pass as PATTERN (A) = 1,8,7,4,5,6,3,2,9,0 in brackets ()
123457057755788586793484204221471661878423(1)
123457057755792039279035948691218229622732(8)
123457057755795491764587693225330802852029(7)
123457057755798944250139437823809381566314(4)
123457057755802396735691182486653965765587(5)
123457057755805849221242927213864555449849(6)
123457057755809301706794672005441150619101(3)
123457057755812754192346416861383751273343(2)
123457057755816206677898161781692357412575(9)
123457057755819659163449906766366969036800(0)
Your first (10) Numbers let's see if they Pass as PATTERN (B) = 7,9,7,1,1,7,9,7,1 in brackets ()
1234570577558077903820610782563862681159521
DIFFERENCE = 8.385742522817317e+36 : PATTERN B = (7)?
1234578963300600764248728267290289327790208
DIFFERENCE = 8.385791345315556e+36 : PATTERN B = (9)?
1234587349091946113381524138491336181010667
DIFFERENCE = 8.385840168123281e+36 : PATTERN B = (7)?
1234595734932114188092585109001774777647104
DIFFERENCE = 8.385888990931005e+36 : PATTERN B = (1)?
1234604120821105225256417288321736157578125
DIFFERENCE = 8.3859378143577e+36 : PATTERN B = (1)?
1234612506758919461748446185293104905117056
DIFFERENCE = 8.385986637629651e+36 : PATTERN B = (7)?
1234620892745557134445016710775918384436823
DIFFERENCE = 8.386035461365831e+36 : PATTERN B = (9)?
1234629278781018480223393180324771169042432
DIFFERENCE = 8.386084285256753e+36 : PATTERN B = (7)?
1234637664865303735961759316865224665296089
DIFFERENCE = 8.386133109302417e+36 : PATTERN B = (1)?
1234646050998413138539218253370221930000000
Your Second (10) Numbers let's see if they Pass as PATTERN (B) = 7,9,7,1,1,7,9,7,1 in brackets ()
1234570577557885867934842042214716618784231
DIFFERENCE = 3.4507578595079975e+28 : PATTERN B = (7)?
1234570577557920392790359486912182296227328
DIFFERENCE = 3.4507578595079975e+28 : PATTERN B = (9)?
1234570577557954917645876932253308028520297
DIFFERENCE = 3.4507578595079975e+28 : PATTERN B = (7)?
1234570577557989442501394378238093815663144
DIFFERENCE = 3.4507578595079975e+28 : PATTERN B = (1)?
1234570577558023967356911824866539657655875
DIFFERENCE = 3.4507578595079975e+28 : PATTERN B = (1)?
1234570577558058492212429272138645554498496
DIFFERENCE = 3.4507578595079975e+28 : PATTERN B = (7)?
1234570577558093017067946720054411506191013
DIFFERENCE = 3.4507578595079975e+28 : PATTERN B = (9)?
1234570577558127541923464168613837512733432
DIFFERENCE = 3.4507578595079975e+28 : PATTERN B = (7)?
1234570577558162066778981617816923574125759
DIFFERENCE = 3.4662321099990648e+28 : PATTERN B = (1)?
1234570577558196591634499067663669690368000
Your first (10) Numbers let's see if they Pass as PATTERN (C) = 1,4,9,6,5,6,9,4,1,0 in brackets ()
1234570577558077903820610782563862681159521 : DIVIDE COUNT 1 = 1.234570577558078e+42 (1)?
1234578963300600764248728267290289327790208 : DIVIDE COUNT 2 = 6.172894816503004e+41 (4)?
1234587349091946113381524138491336181010667 : DIVIDE COUNT 3 = 4.11529116363982e+41 (9)?
1234595734932114188092585109001774777647104 : DIVIDE COUNT 4 = 3.0864893373302856e+41 (6)?
1234604120821105225256417288321736157578125 : DIVIDE COUNT 5 = 2.4692082416422102e+41 (5)?
1234612506758919461748446185293104905117056 : DIVIDE COUNT 6 = 2.057687511264866e+41 (6)?
1234620892745557134445016710775918384436823 : DIVIDE COUNT 7 = 1.7637441324936532e+41 (9)?
1234629278781018480223393180324771169042432 : DIVIDE COUNT 8 = 1.5432865984762731e+41 (4)?
1234637664865303735961759316865224665296089 : DIVIDE COUNT 9 = 1.3718196276281153e+41 (1)?
1234646050998413138539218253370221930000000 : DIVIDE COUNT 10 = 1.2346460509984131e+41 (0)?
Your Second (10) Numbers let's see if they Pass as PATTERN (C) = 1,4,9,6,5,6,9,4,1,0 in brackets ()
1234570577557885867934842042214716618784231 : DIVIDE COUNT 1 = 1.234570577557886e+42 (1)?
1234570577557920392790359486912182296227328 : DIVIDE COUNT 2 = 6.172852887789602e+41 (4)?
1234570577557954917645876932253308028520297 : DIVIDE COUNT 3 = 4.1152352585265165e+41 (9)?
1234570577557989442501394378238093815663144 : DIVIDE COUNT 4 = 3.0864264438949736e+41 (6)?
1234570577558023967356911824866539657655875 : DIVIDE COUNT 5 = 2.4691411551160478e+41 (5)?
1234570577558058492212429272138645554498496 : DIVIDE COUNT 6 = 2.0576176292634308e+41 (6)?
1234570577558093017067946720054411506191013 : DIVIDE COUNT 7 = 1.7636722536544184e+41 (9)?
1234570577558127541923464168613837512733432 : DIVIDE COUNT 8 = 1.5432132219476594e+41 (4)?
1234570577558162066778981617816923574125759 : DIVIDE COUNT 9 = 1.3717450861757356e+41 (1)?
1234570577558196591634499067663669690368000 : DIVIDE COUNT 10 = 1.2345705775581966e+41 (0)?
I really hope after this no one will Question my Genius! unless they have a very good counter proof to my FLT DEMONSTRATION (SOLVED 1998)
A.R.B
#18 Re: This is Cool » Fermats Last Theorem Demonstration! by, Anthony.R.Brown (1998 Solved ) » 2024-04-10 11:18:46
The FLT Demonstration program I made was made FREE! on a budget! It satisfies to show the Three Patterns A,B,C for the accuracy of the program up to certain level.
For anyone wishing to take it further? then please pay for the time on a Super Computer?
Professional Mathematicians have had to do so regarding the work they have been doing like calculating Pi.
I am not in a position to do that,and I don't have the time to do it,I am sure there is someone out there who is willing to test my Three Patterns A,B,C as they get closer to the end of Infinity??? smile
Even more pi in the sky: Calculating 100 trillion digits of pi on Google Cloud...
Pi in the sky: Calculating a record-breaking 31.4 trillion digits of Archimedes’ constant on Google Cloud...
https://cloud.google.com/blog/products/compute/calculating-31-4-trillion-digits-of-archimedes-constant-on-google-cloud
For what it's worth? you wrote...
(one is a cube, the other is a non-cube power, the two numbers are from different groups of ten and are the first number in their group, and both groups satisfy the A,B,C Patterns):
1234570577558077903820610782563862681159521
1234570577558058492212429272138645554498496
Your first group of 10 numbers?
(1) 1234570577558077903820610782563862681159521
Below show us the next 9 in your group of 10 ?
(2)?
(3)?
(4)?
(5)?
(6)?
(7)?
(8)?
(9)?
(10)?
Your Second group of 10 numbers? are already wrong! with the first number..
(1) 1234570577558058492212429272138645554498496 The (6) at the end does not match Pattern A,B,or C as a first number in a group of 10
Below show us the next 9 in your group of 10 ?
(2)?
(3)?
(4)?
(5)?
(6)?
(7)?
(8)?
(9)?
(10)?
PATTERN (A) = 1,8,7,4,5,6,3,2,9,0 in brackets ()
PATTERN (B) = 7,9,7,1,1,7,9,7,1 in brackets ()
PATTERN (C) = 1,4,9,6,5,6,9,4,1,0 in brackets ()
#19 Re: This is Cool » Fermats Last Theorem Demonstration! by, Anthony.R.Brown (1998 Solved ) » 2024-04-01 08:22:32
This has already been shown before with (Xn,Yn,Zn) n < 3
Just because you can show some other numbers that end with the Patterns A,B,C they mean nothing if they are not related to the problem,my Patterns for A,B,C are shown to be cube numbers,which are related to the Original problem below..
The Problem is as follows...
Are there any whole numbers e.g (x,y,z) cube numbers
where x3 + y3 = z3 NOTICE = (Xn,Yn,Zn) n Must be greater than (2)
an example that does not work is given below "
x = 64 cube y = 64 cube Z = 125 cube X + Y = 128 (+ 3) > Z
Below is a good example like what you are putting forward that proves FLT is wrong? but it is not a counter proof because it's not related to the Original problem in any way!
If you could use zero?? then the answer would be
x = 0 y = 0 z = 0 simple! X + Y = Z
#20 Re: This is Cool » Why is this number everywhere? 37 ? » 2024-03-31 03:58:18
This is quite Amazing!
National Lotto Statistics... on 31.03.2024
https://www.national-lottery.com/lotto/statistics
Hot Numbers (Most Common)
Ball Number Frequency Last Drawn
37 110 1 day ago So back to the number 37 being a Human & Machine favourite!
(Sat 30th Mar 2024)
52 108 148 days ago
(Sat 4th Nov 2023)
39 106 32 days ago
(Wed 28th Feb 2024)
58 105 25 days ago
(Wed 6th Mar 2024)
27 102 4 days ago
(Wed 27th Mar 2024)
42 102 4 days ago
(Wed 27th Mar 2024)
Cold Numbers (Most Overdue)
Ball Number Last Drawn
13 218 days ago And the number 13 as being the most unlucky!
(Sat 26th Aug 2023)
52 148 days ago
(Sat 4th Nov 2023)
31 99 days ago
(Sat 23rd Dec 2023)
23 85 days ago
(Sat 6th Jan 2024)
30 74 days ago
(Wed 17th Jan 2024)
38 71 days ago
(Sat 20th Jan 2024)
#21 Re: This is Cool » Why is this number everywhere? 37 ? » 2024-03-30 21:46:14
Yes it's very funny how a number can have kind of Mystical properties?
I remember some years ago when I was a bit green,I thought I could find an advantage with the frequency count of Lottery numbers,and boy did I get a surprise with the number 13,I found it was genuinely unlucky!?
Sure enough nothing has changed?...
Number 13 really IS found to be the Lottery's 'unluckiest' number...
https://www.standard.co.uk/hp/front/number-13-really-is-found-to-be-the-lotterys-unluckiest-number-6659498.html
#22 This is Cool » Why is this number everywhere? 37 ? » 2024-03-30 05:49:03
- AnthonyRBrown
- Replies: 3
https://www.youtube.com/watch?v=d6iQrh2TK98
Maybe someone else can explain this? is there any Hard Math proof for the preference for the number 37 ? or is it all a bit of luck! ?
A.R.B
#23 Re: This is Cool » The Oldest Unsolved Problem in Math ? » 2024-03-26 22:22:19
Below are the first 10 Perfect numbers,so if we can find a related Pattern amongst them? then I might be able to pull of a another FLT Demonstration only this time is will be a PND Perfect Number Demonstration!
6
28
496
8128
33550336
8589869056
137438691328
2305843008139952128
2658455991569831744654692615953842176
191561942608236107294793378084303638130997321548169216
How to Find Perfect Number?
We can easily find perfect numbers using the following steps:
Perfect numbers are positive integers n such that n=s(n),
where, s(n) is the restricted divisor function (i.e., the sum of proper divisors of n), or equivalently
sigma(n)=2n,
where sigma(n) is the divisor function (i.e., the sum of divisors of n including n itself). For example, the first few perfect numbers are 6, 28, 496, 8128, … (OEIS A000396), since
6 = 1+2+3
28 = 1+2+4+7+14
496 = 1+2+4+8+16+31+62+124+248,
Perfect Numbers Solved Examples
Solved Example: Find out if 496 is a perfect number.
Solution: The proper factors of 496 are 1, 2, 4, 8, 16, 31, 62, 124, and 248
1 + 2 + 4 + 8 + 16 + 31 + 62 + 124 + 248 = 496
496 is perfect.
#24 Re: This is Cool » The Oldest Unsolved Problem in Math ? » 2024-03-24 07:03:17
Great stuff Bob iit looks like you have been there before
For the moment it looks like there is enough of a problem finding something in the first 5 numbers! the fifth number is a real Monster and looks like it's a made up hoax,I have never seen such a difference within a small group of related numbers?
#25 Re: This is Cool » The Oldest Unsolved Problem in Math ? » 2024-03-23 22:54:10
Wow! I thought you had stumbled onto something here. But I did a bit of googling and found this
https://byjus.com/maths/perfect-numbers … 033550336.
If you look at how they are formed from that formula you'll see the connection with binary numbers. You just hadn't quite got the general term. Nice try
Bob
Ok! So the next 5th perfect number is not 130816 ? it is 33550336 ?
If we convert that to Binary we get 1111111111111000000000000 ?
Let's compare that with the first 4 perfect numbers below...
6 = 110
28 = 11100
496 = 111110000
8128 = 1111111000000
33550336 = 1111111111111000000000000
What happened to the (All the next perfect numbers should continue like,the 1's are +2 and the 0's are +2) ?
The next 5th perfect number should be...
130816 = 11111111100000000
And it's not! Oh dear this looks like a very hard problem! I will have to give this more than 5 minutes!
A.R.B