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I think so.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Ok.
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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A continuation to the Bullfrog Problem(#562),
'B' solves the given problem (using the same information as given in post no. 562 ) for some value of probability p < 1/6 and the 2 values of n that he gets are 5/2 & 7/6. Is it possible that B has solved the problem correctly?
Last edited by 123ronnie321 (2011-04-27 02:07:58)
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Hi 123ronnie321;
Yes, I believe that all n = 7 / 6 to n = 2.5 and a little bit more than that have the same probability. I have a drawing but I can not upload it to the site.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi 123ronnie321;
Are you clear on it now? If not what question would you like answered? I do not know what you are asking.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi bobbym,
Yes, I am clear with it now.
I will be back in some time with some drawings. I am a bit busy now.
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That is okay. I would like to see them.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi bobbym,
I am confused. I do not understand your statement although it appeared correct to me till yesterday-
I believe that all n = 7 / 6 to n = 2.5 and a little bit more than that have the same probability.
This is what i think ---- for probability p = 1/6 there will be only one solution n = sqrt(3)
and for a fixed probability p < 1/6 there will be exactly two solutions.
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Hi 123ronnie321;
When I get the drawing uploaded it will clear this up.
In the meantime, If you think of the two tangents as now going through the 1 meter circle of course points on the smaller circle's circumference are solutions but so are all the other points between them. They are also within 1 meter.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi;
I am currently in the middle of trying to upload an image that should make it clear to both of us.
See the points p1, p2, p3, p4 they are all solutions for some n. All the points in between then and a little beyond have the 41.4 degrees , so they have the same probability and they are within 1 meter.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi Bobbym,
In your diagram, n = length of segment BP1 & n = length of segment BP3 are the only solutions for probability = 41.7/360. This is what i think. Am i right?
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Pick any two more points between P1 and P3 and P2 and P4 (and on BP2 and BP4 ) and they have a different n but the same probability because they are still 41.7 degrees. The red circle and the green circle represent two possible n's. You can make an infinite number of circles through B that fall inside of the blue circle ( 1 meter ).
Only 60 degrees has 1 unique answer that is why the poser picked it.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi Bobbym,
But if you pick any point between P1 and P3 and name it say P5 and then draw an arc centered at B passing through P5, you will find that the portion of arc inside the 1 meter circle subtends at B an angle greater than 41.7. Thus the probability will differ, wont it?
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Not from the two points they will all have the same angle. I am showing another drawing. Each red circle because the points are all on the same lines all have the same angle and therefore the same probability. Only the n's ( radii of each circle is different.) Angle GBH and angle EBF and angle P3 B P4 are all 41.7 degrees. So P3 and P4 and E and F and G and H are all solutions for different n.
You see each red circle represents all possible jumps for a particular n from B. The angle from B (41.7 degrees ) in those circles represents the probabilities. The area that is covered inside of the small 1 meter ( blue circle ) does not matter. Just as long as the angular measure of the circumference of each red circle is inside of the blue one.
Arc P1P2 is 41.7° of the smallest red circle shown and is inside of the blue circle so P1 and P2 are solutions.
Arc EF is 41.7° of the next red circle shown and is inside of the blue circle so E and F are solutions.
Arc GH is 41.7° of the next red circle shown and is inside of the blue circle so G and H are solutions.
Arc P3P4 is 41.7° of the largest red circle shown and is inside of the blue circle so P3 and P4 are solutions.
You can see now that we can make many circles each being a solution. The 60° problem was a tangent so you could only have one solution. The rest of the angles have none or an infinite number of solutions.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi Bobbym,
Thank you so much for your time!
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Hi 123ronnie321;
You are welcome. Thanks for looking at the problem.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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New problem!
Prove
A says) I got it!
B says) Yep!
C says) Me too!
D says) That is a tough one!
E says) Too easy!
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi bobbym,
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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Hi gAr;
Very good! Can you find an even simpler idea than those 2?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I thought I could get something from (a+b+c)^2, but couldn't get further.
I don't know!
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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Hi gAr;
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi bobbym,
That's nice too!
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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Yes it is, but who the heck can see that!
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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but who the heck can see that!
bobbym!
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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