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#1 2009-07-15 00:50:40

Identity
Member
Registered: 2007-04-18
Posts: 934

Average acceleration

A particle moves in a line with velocity

given by
. The object starts from the origin. Find the average acceleration over the third second.

The answer is

but no matter what I try I can't seem to get it.

If t=0 to t=1 is the first second, then t = 2 to t = 3 should be the third second, but I've found v(3)-v(2) and it's still not right!

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#2 2009-07-15 01:58:17

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Average acceleration

Hi Identity;


Use mathsys method below:

Last edited by bobbym (2009-07-15 06:50:44)


In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#3 2009-07-15 02:11:03

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: Average acceleration

Your way should work too, Identity.
Technically, it's:

But that's the same as what you had, so you shouldn't be getting a different answer.


Why did the vector cross the road?
It wanted to be normal.

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#4 2009-07-15 22:36:51

Identity
Member
Registered: 2007-04-18
Posts: 934

Re: Average acceleration

Thanks, maybe the book was wrong

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#5 2009-07-16 00:07:27

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: Average acceleration

I agree with the book's answer.

v(3) - v(2) = 3/10 - 2/5 = -0.1


Why did the vector cross the road?
It wanted to be normal.

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#6 2009-07-16 03:01:11

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Average acceleration

Hi identity;

I do too.

Average acceleration = Δv/Δt = -.01 m/s^2


In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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