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A particle moves in a line with velocity
given by . The object starts from the origin. Find the average acceleration over the third second.The answer is but no matter what I try I can't seem to get it.
If t=0 to t=1 is the first second, then t = 2 to t = 3 should be the third second, but I've found v(3)-v(2) and it's still not right!
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Hi Identity;
Use mathsys method below:
Last edited by bobbym (2009-07-15 06:50:44)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Your way should work too, Identity.
Technically, it's:
But that's the same as what you had, so you shouldn't be getting a different answer.
Why did the vector cross the road?
It wanted to be normal.
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Thanks, maybe the book was wrong
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I agree with the book's answer.
v(3) - v(2) = 3/10 - 2/5 = -0.1
Why did the vector cross the road?
It wanted to be normal.
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Hi identity;
I do too.
Average acceleration = Δv/Δt = -.01 m/s^2
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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