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#1 2013-01-18 21:13:03

kjames
Guest

mixture problem

HELP!!!
A 90% KCN solution is diluted with water to make a solution of 60% acid. When 3 gallons of water is added to dilute it again, the solution becomes 40% acid.
a. how much water was added to the solution on the first instance?
b. what was the original volume of the 90% acid solution?

#2 2013-01-18 22:00:19

bobbym
Administrator

Online

Re: mixture problem

Hi;

K = the amount of KCN
w = the amount of water
a = amount of water added







K = 2 / 5

w = 18 / 5

a = 2

You should be able to answer a and b now.

By the way, KCN is the salt of a strong base KOH and a weak acid HCN therefore is it a base not an acid.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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