Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**kjames****Guest**

HELP!!!

A 90% KCN solution is diluted with water to make a solution of 60% acid. When 3 gallons of water is added to dilute it again, the solution becomes 40% acid.

a. how much water was added to the solution on the first instance?

b. what was the original volume of the 90% acid solution?

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 84,183

Hi;

K = the amount of KCN

w = the amount of water

a = amount of water added

K = 2 / 5

w = 18 / 5

a = 2

You should be able to answer a and b now.

By the way, KCN is the salt of a strong base KOH and a weak acid HCN therefore is it a base not an acid.

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

Offline

Pages: **1**