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**dford****Member**- Registered: 2013-12-06
- Posts: 4

Hi this is my first post here.

On the puzzle ABCD × E = DCBA

Should it not be, (A)(B)(C)(D) x E = (D)(C)(B)(A)

There for A, B, C, D can be anything as long as E = 1 or 0?

If this has been discussed before sorry.

Thanks all!

*Last edited by dford (2013-12-06 17:04:33)*

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**roniman****Member**- Registered: 2013-11-24
- Posts: 22

(A)(B) is like (2)(4), which would mean 2x4.

AB is like 24

So if A =2, B = , C = , D = 8, and E = 4, then

2178

x 4

--------

8712

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,237

Hi;

Another solution is 1089 * 9 = 9801 provided there is no condition that all the numbers have to be different.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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