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#1 2013-12-06 17:00:12

dford
Member
Registered: 2013-12-06
Posts: 4

ABCD x E Puzzle - Solution ?

Hi this is my first post here.

On the puzzle ABCD × E = DCBA

Should it not be, (A)(B)(C)(D) x E = (D)(C)(B)(A)

There for A, B, C, D can be anything as long as E = 1 or 0?

If this has been discussed before sorry.

Thanks all!

Last edited by dford (2013-12-06 17:04:33)

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#2 2013-12-06 18:54:42

roniman
Member
Registered: 2013-11-24
Posts: 22

Re: ABCD x E Puzzle - Solution ?

(A)(B) is like (2)(4), which would mean 2x4.

AB is like 24

So if A =2, B = , C = , D = 8, and E = 4, then
  2178
x     4
--------
  8712

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#3 2013-12-06 22:56:54

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 83,249

Re: ABCD x E Puzzle - Solution ?

Hi;

Another solution is 1089 * 9 = 9801 provided there is no condition that all the numbers have to be different.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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