Hi this is my first post here.
On the puzzle ABCD × E = DCBA
Should it not be, (A)(B)(C)(D) x E = (D)(C)(B)(A)
There for A, B, C, D can be anything as long as E = 1 or 0?
If this has been discussed before sorry.
Last edited by dford (2013-12-06 17:04:33)
(A)(B) is like (2)(4), which would mean 2x4.
AB is like 24
So if A =2, B = , C = , D = 8, and E = 4, then
Another solution is 1089 * 9 = 9801 provided there is no condition that all the numbers have to be different.
In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.