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#1 2013-12-06 17:00:12

dford
Member
Registered: 2013-12-06
Posts: 4

ABCD x E Puzzle - Solution ?

Hi this is my first post here.

On the puzzle ABCD × E = DCBA

Should it not be, (A)(B)(C)(D) x E = (D)(C)(B)(A)

There for A, B, C, D can be anything as long as E = 1 or 0?

If this has been discussed before sorry.

Thanks all!

Last edited by dford (2013-12-06 17:04:33)

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#2 2013-12-06 18:54:42

roniman
Member
Registered: 2013-11-24
Posts: 22

Re: ABCD x E Puzzle - Solution ?

(A)(B) is like (2)(4), which would mean 2x4.

AB is like 24

So if A =2, B = , C = , D = 8, and E = 4, then
  2178
x     4
--------
  8712

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#3 2013-12-06 22:56:54

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 87,258

Re: ABCD x E Puzzle - Solution ?

Hi;

Another solution is 1089 * 9 = 9801 provided there is no condition that all the numbers have to be different.


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

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