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#1 2013-12-10 22:21:34



another odds ratio case

in online game, two team fight against each other

team a   strength  73% ,which corespond to 100% (for conveniece, here note 73)
team b   strenth   46

then odds ratio =73/(100-73)/ (46/(100-46)=73/27/(45/55)
no problem here

suppose team;s strength divided into two part  attck and defense
team a  attack=44    defense=6
team b  attack=64    defense=33
where 100 correspoinds to the best rank

in odds ratio formula, winthin a group ,  p,  100-p

since attack+defense is not equal to 100, which puzzled me.
I use several method,

for conveniece
team a attack note m
team a defense n
team b attck o
team b defense p

method 1
strenth=(attack +defense)/2   algebra average value
then use the fumula of odds ratio
odds ratio=((m+n)/2)(100-(m+n)/2)/ ( ((o+p)/2)/(100-((o+p)/2)))

method 2
strength=sqrt((attack +defense) geometry average value

methd 3
regard defense is unlike probilities,juse use odds ratio formula directly
odds ratio=m/p /(o/n)

method 4 

odds ratio= m/(100-m)/(p/(100-p))/  (o/(100-o)/(n/(100-n)))

method XX

which is right? or they were all wrong ? any solution pls give me help?

how to calculate odds ratio?

Last edited by extjsjquery (2013-12-10 22:43:56)

#2 2013-12-11 00:47:44



Re: another odds ratio case


I am not sure what you are trying to do here. The OR as far as I know is finding the correlation between binary data. How does what you are doing relate to that?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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