in online game, two team fight against each other
team a strength 73% ,which corespond to 100% (for conveniece, here note 73)
team b strenth 46
then odds ratio =73/(100-73)/ (46/(100-46)=73/27/(45/55)
no problem here
suppose team;s strength divided into two part attck and defense
team a attack=44 defense=6
team b attack=64 defense=33
where 100 correspoinds to the best rank
in odds ratio formula, winthin a group , p, 100-p
since attack+defense is not equal to 100, which puzzled me.
I use several method,
team a attack note m
team a defense n
team b attck o
team b defense p
strenth=(attack +defense)/2 algebra average value
then use the fumula of odds ratio
odds ratio=((m+n)/2)(100-(m+n)/2)/ ( ((o+p)/2)/(100-((o+p)/2)))
strength=sqrt((attack +defense) geometry average value
regard defense is unlike probilities,juse use odds ratio formula directly
odds ratio=m/p /(o/n)
odds ratio= m/(100-m)/(p/(100-p))/ (o/(100-o)/(n/(100-n)))
which is right? or they were all wrong ? any solution pls give me help?
how to calculate odds ratio?
Last edited by extjsjquery (2013-12-09 23:43:56)
I am not sure what you are trying to do here. The OR as far as I know is finding the correlation between binary data. How does what you are doing relate to that?
In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.