You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**extjsjquery****Member**- Registered: 2013-12-09
- Posts: 4

in online game, two team fight against each other

here

team a strength 73% ,which corespond to 100% (for conveniece, here note 73)

team b strenth 46

then odds ratio =73/(100-73)/ (46/(100-46)=73/27/(45/55)

no problem here

suppose team;s strength divided into two part attck and defense

team a attack=44 defense=6

team b attack=64 defense=33

where 100 correspoinds to the best rank

in odds ratio formula, winthin a group , p, 100-p

since attack+defense is not equal to 100, which puzzled me.

I use several method,

for conveniece

team a attack note m

team a defense n

team b attck o

team b defense p

method 1

strenth=(attack +defense)/2 algebra average value

then use the fumula of odds ratio

odds ratio=((m+n)/2)(100-(m+n)/2)/ ( ((o+p)/2)/(100-((o+p)/2)))

method 2

strength=sqrt((attack +defense) geometry average value

methd 3

regard defense is unlike probilities,juse use odds ratio formula directly

odds ratio=m/p /(o/n)

method 4

odds ratio= m/(100-m)/(p/(100-p))/ (o/(100-o)/(n/(100-n)))

method XX

......

...

which is right? or they were all wrong ? any solution pls give me help?

how to calculate odds ratio?

*Last edited by extjsjquery (2013-12-09 23:43:56)*

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,656

Hi;

I am not sure what you are trying to do here. The OR as far as I know is finding the correlation between binary data. How does what you are doing relate to that?

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

Pages: **1**