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**Zeeshan 01****Member**- Registered: 2016-07-22
- Posts: 648

What is extreme values and question explain

Find the extreme values for the function defined as

f (x)=1-x^3

MZk

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

You are looking for the maxima and minima? You will need calculus for that. You could compute them easy enough. So, what type of answer are you looking for?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**Zeeshan 01****Member**- Registered: 2016-07-22
- Posts: 648

Find the extreme values for the function defined as

f (x)=1-x^3

I need how to solve it

MZk

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**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,108

The extreme value theorem is here:

https://www.khanacademy.org/math/ap-cal … ue-theorem

If that function has no defined domain then the extremes are + and - infinity. But I would expect to have been given a range of values for x. Are you sure you are giving us the whole question?

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**Zeeshan 01****Member**- Registered: 2016-07-22
- Posts: 648

yes its complete question its maxima and minima method

MZk

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

To find candidates to be a local extreme we differentiate the function.

We set that to 0 and solve:

The only roots are 0 and 0. So (0,1) is a possible local extreme.

But using the second derivative test

we see that 1 - x^3 does not have a maxima or a minima at x = 0 so I would say that 1 - x^3 does not have any local extremes.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**Zeeshan 01****Member**- Registered: 2016-07-22
- Posts: 648

Why

We set that to 0 and solve:

MZk

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**Zeeshan 01****Member**- Registered: 2016-07-22
- Posts: 648

The only roots are 0 and 0. So (0,1) is a possible local extreme.

Why you not wote (0,1)

How y axis is 1

MZk

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

When you put x = 0 into y = 1 -x^3 you get 1. Therefore the point is (0,1).

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**CIV****Member**- Registered: 2014-11-09
- Posts: 66

Zeeshan 01 wrote:

The only roots are 0 and 0. So (0,1) is a possible local extreme.

Why you not wote (0,1)

How y axis is 1

The location of the extrema is x = 0. The location of the tangent line, when it's slope is zero, is (0,1)

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