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#1 2017-03-08 17:51:04

Zeeshan 01
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Registered: 2016-07-22
Posts: 746

Extreme values

What is extreme values and question explain

Find the extreme values for the function defined as
f (x)=1-x^3


Malik

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#2 2017-03-08 20:25:57

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Extreme values

You are looking for the maxima and minima? You will need calculus for that. You could compute them easy enough. So, what type of answer are you looking for?


In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#3 2017-03-09 00:02:19

Zeeshan 01
Member
Registered: 2016-07-22
Posts: 746

Re: Extreme values

Find the extreme values for the function defined as
f (x)=1-x^3
I need how to solve it


Malik

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#4 2017-03-09 01:17:52

Bob
Administrator
Registered: 2010-06-20
Posts: 10,053

Re: Extreme values

The extreme value theorem is here:

https://www.khanacademy.org/math/ap-cal … ue-theorem

If that function has no defined domain then the extremes are + and - infinity.  But I would expect to have been given a range of values for x.  Are you sure you are giving us the whole question?

Bob


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob smile

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#5 2017-03-09 01:24:37

Zeeshan 01
Member
Registered: 2016-07-22
Posts: 746

Re: Extreme values

yes its complete question its maxima and minima method


Malik

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#6 2017-03-09 01:52:05

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Extreme values

Hi;

To find candidates to be a local extreme we differentiate the function.

We set that to 0 and solve:

The only roots are 0 and 0. So (0,1) is a possible local extreme.

But using the second derivative test

we see that 1 - x^3 does not have a maxima or a minima at x = 0 so I would say that 1 - x^3 does not have any local extremes.


In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#7 2017-03-10 15:01:24

Zeeshan 01
Member
Registered: 2016-07-22
Posts: 746

Re: Extreme values

Why
We set that to 0 and solve:


Malik

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#8 2017-03-10 15:03:27

Zeeshan 01
Member
Registered: 2016-07-22
Posts: 746

Re: Extreme values

The only roots are 0 and 0. So (0,1) is a possible local extreme.
Why you not wote (0,1)
How y axis is 1


Malik

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#9 2017-03-10 16:10:20

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Extreme values

When you put x = 0 into y = 1 -x^3 you get 1. Therefore the point is (0,1).


In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#10 2017-03-12 01:00:49

CIV
Member
Registered: 2014-11-09
Posts: 74

Re: Extreme values

Zeeshan 01 wrote:

The only roots are 0 and 0. So (0,1) is a possible local extreme.
Why you not wote (0,1)
How y axis is 1

The location of the extrema is x = 0. The location of the tangent line, when it's slope is zero, is (0,1)

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