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**Geometry Help****Guest**

Find $AC$ in the following triangle, to two decimal places.

[asy]

unitsize(2 cm);

pair A, B, C;

A = dir(40);

B = (0,0);

C = (3,0);

draw(A--B--C--cycle);

label("$A$", A, N);

label("$B$", B, SW);

label("$C$", C, SE);

label("$1$", (A + B)/2, NW);

label("$3$", (B + C)/2, S);

label("$40^\circ$", B + (0.5,0.15));

[/asy]

Can you give me a solution leading to an answer?

I just need confirmation what i'm doing is correct.

**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,417

hi Geometry Help

Welcome to the forum.

I'd like to help but I cannot understand your notation. I have got no hits by searching for [asy]. I've tried drawing a diagram as follows:

1. Mark coordinate axes.

2. Plot B (0,0) and C (3,0)

3. Draw a line from B to A (unknown position) so that angle ABC = 40 degrees.

Then I'm stuck.

Please would you re-post with a written description of the diagram, like the one I have put here.

Thanks,

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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