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Geometry Help

Guest

Geometry Help

Find $AC$ in the following triangle, to two decimal places.

[asy]
unitsize(2 cm);

pair A, B, C;

A = dir(40);
B = (0,0);
C = (3,0);

draw(A--B--C--cycle);

label("$A$", A, N);
label("$B$", B, SW);
label("$C$", C, SE);
label("$1$", (A + B)/2, NW);
label("$3$", (B + C)/2, S);
label("$40^\circ$", B + (0.5,0.15));
[/asy]

Can you give me a solution leading to an answer?
I just need confirmation what i'm doing is correct.

Bob

Administrator

Registered: 2010-06-20

Posts: 10,140

Re: Geometry Help

hi Geometry Help

Welcome to the forum.

I'd like to help but I cannot understand your notation.  I have got no hits by searching for [asy].  I've tried drawing a diagram as follows:

1.  Mark coordinate axes.

2. Plot B (0,0) and C (3,0)

3. Draw a line from B to A (unknown position) so that angle ABC = 40 degrees.

Then I'm stuck.

Please would you re-post with a written description of the diagram, like the one I have put here.

Thanks,

Bob

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Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob