Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2006-10-02 21:35:18

runlemmingsrun1
Guest

curve of graph

For the equation Y=X^2-X,  the graph is a parabola that opens upward... Please let me know what other description can be added to it??

  Thanks...

#2 2006-10-03 01:29:30

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: curve of graph

Do you just need to describe it with words? If so, the only other thing I can think of would be that its minimum point is below and to the right of the origin.

If you can use numbers or co-ordinates, then you could give the locations of where it crosses the axes and where its turning point is. And it doesn't apply to this graph, but for others you could also say where asymptotes are.


Why did the vector cross the road?
It wanted to be normal.

Offline

#3 2006-10-03 01:36:25

runlemmingsrun1
Guest

Re: curve of graph

It has to be described in words.but any extra information is welcome too..thanks

#4 2006-10-03 16:54:47

George,Y
Member
Registered: 2006-03-12
Posts: 1,379

Re: curve of graph

Y= X^2-X
= (X-1/2)^2-1/4 >= -1/4
So the parabola has its lowest point (1/2, -1/4)

Y=X^2-X= X(X-1)
So the parabola intersects x-axis at (0,0) and (1,0).


X'(y-Xβ)=0

Offline

Board footer

Powered by FluxBB