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For the equation Y=X^2-X, the graph is a parabola that opens upward... Please let me know what other description can be added to it??
Thanks...
Do you just need to describe it with words? If so, the only other thing I can think of would be that its minimum point is below and to the right of the origin.
If you can use numbers or co-ordinates, then you could give the locations of where it crosses the axes and where its turning point is. And it doesn't apply to this graph, but for others you could also say where asymptotes are.
Why did the vector cross the road?
It wanted to be normal.
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It has to be described in words.but any extra information is welcome too..thanks
Y= X^2-X
= (X-1/2)^2-1/4 >= -1/4
So the parabola has its lowest point (1/2, -1/4)
Y=X^2-X= X(X-1)
So the parabola intersects x-axis at (0,0) and (1,0).
X'(y-Xβ)=0
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