Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

**Kiran****Member**- Registered: 2006-11-15
- Posts: 177

if a certain parabola has its vertex at (2,-1) and its focus at (2,1), write its equation and graph.

(h,k) = (2,-1)

h = 2 k = -1

focus (h,k + p) is (2,1) so k + p = 1

k = -1 p = 2

y - k = 1/4p( x - h)^2 < equation

y - (-1) = 1/4(2) (x - (2))^2 < substituted

y = 1/8 ( x - 2)^2 - 1 < solved

Live 4 Love

Offline

**Kiran****Member**- Registered: 2006-11-15
- Posts: 177

i have to graph it....can you help me on the graphing

Live 4 Love

Offline