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#1 2007-01-02 10:46:36

Kiran
Member
Registered: 2006-11-15
Posts: 177

Correct>?

if a certain parabola has its vertex at (2,-1) and its focus at (2,1), write its equation and graph.

(h,k) = (2,-1)
h = 2  k = -1
focus (h,k + p) is (2,1) so k + p = 1
k = -1  p = 2

y - k = 1/4p( x - h)^2  < equation
y - (-1) = 1/4(2)  (x - (2))^2  < substituted
y = 1/8 ( x - 2)^2 - 1 < solved


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#2 2007-01-03 10:57:09

Kiran
Member
Registered: 2006-11-15
Posts: 177

Re: Correct>?

i have to graph it....can you help me on the graphing


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