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**Primenumbers****Member**- Registered: 2013-01-22
- Posts: 149

Take your number, p, which you want to find out if it's prime or not.

Square root it. Multiply all the primes below the square root together.

Minus p from this number and see if there are any common factors between the two. If there is p is not prime, if there isn't p is prime.

Example:

p=51

square root p=7ish

2*3*5*7=210

210-51=159 common factor=3

51 is not prime

p=53

square root p=7ish

2*3*5*7=210

210-53=157 no common factors

53 is prime.

Note: It is impossible if the two numbers add up to a no. factorable by everything, for one to be factorable by a number and the other not. They must either both be factorable or both not.

**"Time not important. Only life important."*** - The Fifth Element 1997*

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**Primenumbers****Member**- Registered: 2013-01-22
- Posts: 149

I'm not sure but I'm guessing this would be a faster way to compute finding primes. I.e. using Euclid's algorithm.

See............

https://en.wikipedia.org/wiki/Euclidean_algorithm

**"Time not important. Only life important."*** - The Fifth Element 1997*

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**mathaholic****Member**- From: Earth
- Registered: 2012-11-29
- Posts: 3,251

I see the technique. I tried it in several numbers and it worked.

Mathaholic | 10th most active poster | Maker of the 350,000th post | Person | rrr's classmate

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**Primenumbers****Member**- Registered: 2013-01-22
- Posts: 149

A= all the primes below

multiplied togetherIf (A-p) and p do not share a common factor then p = prime.

**"Time not important. Only life important."*** - The Fifth Element 1997*

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

This is called the wheel.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**Lehona****Member**- Registered: 2016-10-22
- Posts: 16

Primenumbers wrote:

I'm not sure but I'm guessing this would be a faster way to compute finding primes. I.e. using Euclid's algorithm.

See............https://en.wikipedia.org/wiki/Euclidean_algorithm

Primality Tests are usually done on numbers in the range of 2^1024 to 2^2048 (or much, much bigger numbers, when it's simply about "finding a prime", not crypto). Enumerating (and multiplying!) all the primes below those numbers is an insurmountable task.

If enumerating all primes was easy, RSA would be useless :-p

Edit: I just saw this thread is kinda old (still first page), I hope this doesn't count as necromancy

*Last edited by Lehona (2016-10-22 09:50:03)*

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**RatnaPrabhu****Member**- Registered: 2019-11-19
- Posts: 6

CHIKA OFILI Test for Divisibility by 7

For Centuries All Top Mathematicians would have had a Go at finding a Test for Divisibility by 7.

Now, a 12 year old Chika Olifi has come out with a very Simple Test.

Consider your Number as AB, where B is the last Digit and A is the rest of the Digits considered as a Single Number.

Chika Ofili Test is to Calculate A + 5B. If that is Divisible by 7, then our Original Number is Divisible by 7.

For Example, . . . Consider 588 . . . A is 58 and B is 8 . . . A + 5B is 58 + 5 * 8 = 98 . . . this being Divisible by 7, it means 588 is Divisible by 7.

This can be Proved by a few simple steps, which our Maths Fans can try out.

RatnaPrabhu, Ahmedabad, INDIA

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**Monox D. I-Fly****Member**- From: Indonesia
- Registered: 2015-12-02
- Posts: 2,000

RatnaPrabhu wrote:

CHIKA OFILI Test for Divisibility by 7

For Centuries All Top Mathematicians would have had a Go at finding a Test for Divisibility by 7.

Now, a 12 year old Chika Olifi has come out with a very Simple Test.

Consider your Number as AB, where B is the last Digit and A is the rest of the Digits considered as a Single Number.

Chika Ofili Test is to Calculate A + 5B. If that is Divisible by 7, then our Original Number is Divisible by 7.For Example, . . . Consider 588 . . . A is 58 and B is 8 . . . A + 5B is 58 + 5 * 8 = 98 . . . this being Divisible by 7, it means 588 is Divisible by 7.

This can be Proved by a few simple steps, which our Maths Fans can try out.

RatnaPrabhu, Ahmedabad, INDIA

That would be useful to answer some circular questions.

Actually I never watch Star Wars and not interested in it anyway, but I choose a Yoda card as my avatar in honor of our great friend bobbym who has passed away.

May his adventurous soul rest in peace at heaven.

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**Knewlogik****Member**- Registered: 2020-05-11
- Posts: 20

Did you know that the number one or number three the number 9 and the number 27 if you continue to add 30 too it as many times as you want and I'm pretty sure can never be a prime 21 +30=51,3+30=33,27+30=57,9+30=39if you noticed none of those are Prime's and any those four numbers you could continue to as 30 2 it's answer forever and now don't never be a prime meaning every third number ending in 1/3 7 or 9 and that form could never be a prime it's eliminate a lot of them

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