Math Is Fun Forum
You are not logged in.
- Topics: Active | Unanswered
Pages: 1
#1 Re: Help Me ! » inquiry based on the noise of graphing software » 2008-01-13 07:16:42
thank you. surprizingly, I found help in a forum for once. I will continue using this forum for my mathematical inquiries. Again, thank you very much LuisRodg.
#2 Re: Help Me ! » inquiry based on the noise of graphing software » 2008-01-13 07:08:44
I am achieving the same result exept x= 1.9987 and x=2.0077.... what should i do? if i round to 2, will he deduct me?
#3 Re: Help Me ! » inquiry based on the noise of graphing software » 2008-01-13 06:31:52
okayy f(x) = (((40+3x+x^2)/500)-0.1)^2 + 0.15 I must find the minimum value between x=0 and x=4. Do not let the straight line appearance fool you. IT IS NOT a straight line. 
#4 Re: Help Me ! » inquiry based on the noise of graphing software » 2008-01-13 06:01:00
I am not taking calculus so I have no idea what you just said haha. I have that course next semester. My question was clear. I have to use graphing software to show this. But there is noise. What do i do?
#5 Re: Help Me ! » Ap Bc Calc » 2008-01-13 05:58:15
oh no you took my pervious post the wrong way. My post is in another page. I do agree that you should answers this persons question. But MINE which is on ANOTHER page (previous to this one) you will find is definitely more worthy of attention.
#6 Re: Help Me ! » Ap Bc Calc » 2008-01-13 05:56:35
no, I have asked One question, which is regarding graphing software.
#7 Re: Help Me ! » Ap Bc Calc » 2008-01-13 05:51:22
What I dont understand Is why no one is answering my post. I have clearly done anything and everything to show that I am insightfull. And yes, Asking people to do your homework is not beneficial at all.
#8 Help Me ! » inquiry based on the noise of graphing software » 2008-01-13 05:25:19
- johnnytheflipper
- Replies: 10
I recently graphed a complicated function on geometer's sketchpad, in hopes that i could determine a local minimum graphically, seeing as that is what the question was asking. I used the trace feature to narrow in on the point I wanted to find, and as I narrows in on that point, I found that there were 2 x-values that were infinitely close to eachother (for example, .38798, and .39124) that produced the same minimum y-value 0.15. I am sure that there is not just a straigh line between these two points seeing as I am dealing with a quartic function.
My question is, Do i take the average between these two points (i dont think so, because it still wouldnt be acturate), or do I state that "the minimum y-value is located Somewhere between these two x-values". I dont want to make this statement because the question specifies to determine a specific x-value graphically.
Thank you very much,
Johnnytheflipper
Pages: 1