You are not logged in.
Pages: 1
Thanks again,
I got the first one but the second one is a bit confusing.......but 4c2 = 4!/2!.2! = 6 then the final answer is 6x6p2 + 6x4c2 = 6x30 + 6x6 = 180+36 = 216.
A meeting involves 4companies, each company sends three representatives- MD,CA,CS.In how many ways can the twelve people can be arranged in a circular table if the three people from each company sit together with MD in between the CS and CA in each case??
This is how I tried....but couldn't get the right answer(96)
Step 1: There are 4 companies sending 3people and all the three people should sit together so there are 4 sets which can be arranged in 4! ways i.e 24 ways
Step 2: MD should alwys be between CS and CA so CS and CS can be arranged in 2! ways i.e 2ways
Hence the total number of ways is 24x2= 48 ways.
But i know i didn't arrange them in a circular table....how can we do that??
Thanks
Thank you for your quick reply.....but the answers are 1596(for selecting 4 letters from the given word) and 198 (containing 2 R's)and no clue how he gets that?? Waiting for your reply
How to find the total number of permutations of four letters selected from the word 'ARRANGEMENT'.How many of these permutations contain two R's??
Pages: 1